The product $A$ in the following reaction is:
$CH_3-CH=CH-CH_2-CN \xrightarrow[(2) H_3O^+]{(1) DIBAL-H, -78^{\circ}C} A$

  • A
    $CH_3-CH=CH-CH_2-COOH$
  • B
    $CH_3-CH_2-CH_2-CH_2-CHO$
  • C
    $CH_3-CH=CH-CH_2-CHO$
  • D
    $CH_3-CH=CH-CH_2-CH_2-NH_2$

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| :--- | :--- |
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